if someone could help with this question
I have a bottle of HCl which is labelled 35% HCl w/w. NB assume the solution density is 1.200 g/cm and the MW of HCl is 36.46g.
what is the molarity of the solution?

1% m/m = 1 g HCl / 100 g solution
35% m/m = 35 g HCl / 100 g solution
100 g solution = 100 g / [1.2 g mL^-1] = 83.333333333333... mL
35 g /83.3333333... mL = [35 x 12] g / 1000 mL = 420 g HCl /L

[HCl] = 420/36.46 = 11.52 M (12 M to 2 sig figs since 35% m/m was 2 sig figs)

7 days later
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