MHS successful candidate (1+2+3+4...infinite) times-72(sin(90))(d/dx(x+C), for the first part, if u know the ramanujan paradox, u will get it
MHS successful candidate chxin that doesn't give u 7 33-15=18times 3 is 54, 54+6-168, btw (1+2+3+4... infinite) perpendicular-4(d/dx(x+C))
MHS successful candidate chxin its fine step bro, 10-(sin(90) + (cos(0) times -12(1+2+3+4... infinite)(d/dx(x+C)
MHS successful candidate chxin i think it was supposed to be 10 , but I guess we are skip coiunting so, -14/12(1+2+3+4... infinite)(d/dx(x+C))(tan(45)) 12 I got a bit bored so put a more readable version now
