MMHS i think he means d because there isnt a value for x but idk about that i also thought it was a but idk

    MMHS
    TryingForMHS

    yes, I have a couple more:

    Question 14
    Consider a right angled triangle where one of the non right angles is α and
    tan α= 4 If the length of the adjacent sides is 7 what is the length of the hypotenuse?
    A: √65
    B: 4/7
    C: √800
    D: √833
    E: 28

    Question 31
    y = 6x + 12

    then, x − 12/x − 3 =

    A: y/y+9
    B: y−24/y−15
    C: y−60/y−6
    D: y−84/y−30
    E: y−12/y−3

          Skyward1264
          for 14, its easier than you think, so according to the trig function Tan, Tan of theta = opp/adj. So, we already know the adjacent is 7. So we can plug that in denominator, now, what number divdes by 7 to get 4. This is of course, 28. Now we know two sides, so now we can use pythag theorem where a2+b2=c2. So, 282+72 = sqrt833

              oh and for 31, the answer is d because just have to make x the subject of the first equation so it would be 6x=12-y. And to make the next equation able to be substituted with x you must times the top and bottom by 6 so you can substitute 12-y or y-12 in it.

              MMHS damn ur actually right and i like how you explain ii but people may think 28 squared is hard but its not just do 28x28

                MMHS

                yea thats a good explanation.ngl it is so satisfying when yk exactly what formula u have to use for a question.

                • MMHS replied to this.

                    Sonic I put Suzanne first but prob going to change it to macrob because schs is too far away

                      How many do u guys get approximately out of 60 for verbal? And for numerical out of 50?

                      • MMHS replied to this.

                        Miio
                        last week for jac i got 48/60 which is like 80%. Its very very hard to get 60/60. Numerical the last week i got 39/50 for jac as well and usually numerical is harder