hi everyone, next year I am starting year 12 and I am taking 3/4 chem. I’ve heard that the jump to 3/4 from 1/2 is very significant in vce and was wondering if anyone had any advice of how to not get overwhelmed with the new content and workload next year? thanks!!

Believe it or not the year 10 --> 1/2 jump in chem is actually larger than the 1/2 --> 3/4 jump. 3/4 is a lot more fun because you see how the stuff you learned in 1/2 is actually relevant e.g. you learn KOHeS in redox without much background in 1/2, but it's only in 3/4 that you learn how redox forms the basis behind the operation of batteries

    Billzene
    wow interesting...we have started transition classes in my school. My chem 3/4 teacher overwhelmed me with heaps of polysaccharides and said how physics(sectors) relate to bonding etc. I am just confused...overall we had around 6 transition class, we got no textbook and only teacher handouts.

    Can u plz give me some tips for 3/4 chem? Tips to survive and ace it.

        Newbie I made a comment about chem 3/4 tips on a post on the old forums, I'll copy-paste it here:

        *Spam practice exams (especially VCAA), dynamicscience is a good resource
        *Practice structural elucidation
        *Focus on the explanation questions since they're marked really pedantically like VCE bio
        *Be really good with electrolysis and experimental design cuz there is always a massive question on one or both of them on the exam
        *Know your organic nomenclature and functional groups
        *Understand Le Chat's rule, it's so useful everywhere you go eg determining charge of zwitterion charge when you get to biochem
        *Know how to use to electrochemical series
        *As an extension to the above, know how to use the data book cuz it's literally Doraemon's pocket
        *If you did physics, you can use dimensional analysis (unit cancelling) to check answers and infer formulas that you've forgotten eg if you're asked to find the number of moles of e-s during electrolysis when given the time, current and Faraday's constant without the formula, you would approach it the following way: since current is in A which is in Coulomb per seconds and time is in seconds, multiply these (cancelling the secs) to acquire a quantity in C, which is a unit of charge. Since you're asked for something in mol, and the Faraday's constant is given in C/mol, you divide the charge you've found in your first step by Faraday's constant to cancel out the Cs and move the mol to the numerator side of the fraction, yielding the correct answer.

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