I am confused with this. I just started methods 1&2 as I am a year 11, and this question came up in "Solving Simultaneous linear and quadratic equation", could anyone help me with this please"

This is the question: "Find the equation of the straight line(s) which pass through the point (1, −2) and is (are)
tangent to the parabola with equation y = x2."

Please help me with this

    Av15

    One equation would be -2 = m x 1 + c

    Equation 2 would require some manipulation. You know that y = mx + c intersects with y = x2, so mx + c = x2 by substitution. Tangent implies one solution, so I'll let you use the determinant to figure this out

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