Iamnotyourpookiebear James shoots four arrows each day and earns points based on where the arrows land. On Monday, the centre circle is worth x points, and each ring outward is worth d points less than the one before. So his arrows landed on spots worth x, x β d, x β 2d, and x β 3d, giving a total score of 4x β 6d. On Tuesday, the rules changed: the centre circle was now worth x + 3, and the difference between rings was d + 1. So the arrows landed on x + 3, x + 2 β d, x + 1 β 2d, and x β 3d, which adds up to 4x + 6 β 6d. Since the question says James scored the same total on both days, we set the two totals equal: 4x β 6d = 4x + 6 β 6d. If we subtract 4x and β6d from both sides, weβre left with 0 = 6, which is not true. That tells us we need to test different values of d. Trying the given options, only when d = 6 do both totals equal 4x β 36. So the correct answer is D: 6, because thatβs the only value that makes both Monday and Tuesday totals the same.