hey
for this questions write an equation that shows hso4- acting as base in water. Would it be. Thank you
h2so4 + h20 = hso4- + h30+
hey
for this questions write an equation that shows hso4- acting as base in water. Would it be. Thank you
h2so4 + h20 = hso4- + h30+
chemistry1111
You’re showing H2SO4 acting as an acid, not HSO4- acting as a base. Remember that bases grab H+ i.e. they neutralise (remove) H3O+ instead of making more H3O+
hamna_fa
Hi!
Edit: I'm completely wrong... Mybad! See Will
Presuming the standard solution is used to make the titrant/aliquot; here's my understanding!
- This would mean that the concentration would have been artificially decreased (as the titrant would be diluted).
- This would mean there would be an overestimation of aliquot added.
Hope this helps!
Is the volumetric flask not supposed to be rinsed with only deionsied water?
It says the "accuracy of the standard solution", so I'm assuming the volumetric flask is used to make the standard solution. If so, it should be washed with water regardless, as water is added to make these, and it is filled up to a certain point in the beaker.
The only thing that is washed with the solution which will go in it is the burette and the pipette, right?
Hi, how does alcohol effect the tertiary structure of a protein?
Greetings,
For mass spectroscopy, do we need to know how to write the equation which produces the parent molecular ions and base peaks?
I saw it on a VCAA 2010 exam, but not sure if it's within the scope of the new study design.
And if so, could anyone provide an example of how you would write it?
Thanks,
Your Lord
Hey guys I have a question.
So I'm doing a gravimetric analysis task tmr where we have to look at the % of sulphate in fertilizer and compare it to the manufacturer's claim.
One of the steps in the experiment is to grind the fertilizer and then mix it with both HCl and distilled water. Then we boil and add barium chloride to form a precipitate.
I was just wondering what the role of the HCl was.
sasushi
A lot of times in fertilisers they also have phosphate in there. Following the solubility rules, barium phosphate is also very insoluble in water, so when you add BaCl2 to the fertiliser which may contain phosphate some Ba2(PO4)3 precipitate may form and you might erroneously include it in the mass of BaSO4 precipitate, which overestimates the sulfate content of the fertiliser. Ba2(PO4)3 is soluble in HCl so adding HCl will prevent it from precipitating such that the final precipitate is exclusively BaSO4
hamna_fa
You have volume and concentration of the Na2S solution so you want to convert that to mol and then you’d use molar ratios to calculate n(CdS) and hence m(CdS)
Cd(NO3)2 in excess = Na2S is limiting which means the amount of Na2S present (not Cd(NO3)2) is important to know if you want to calculate how much CdS precipitate is produced
Hi Billzene!
For VCE purposes; do we need to know how to number carbons in a cyclic molecule?
Eg. For determining if a monosaccharide is alpha or beta?
Thanks in advance
for this question For the boric acid isn’t it 0.89x v1 =1 x 0.15
Stock is C1
But the answer says 133.5g
https://drive.google.com/drive/folders/1qKgLbhtaTwmzOsE-7TBQBFsv-k4HE-xV
Chocolatepistachio no idea why it’s in g. Also it should’ve been 0.890 M x v1 = 0.089 M x 0.15 L
Hii everyone!
I am so confused...
The answer says 5-bromo-2-chloro-4-ethylhexane
but can't it also be
2-bromo-5-chloro-3-ethylhexane
then which one do you prefer?
Please help Thank you!!!
Ps. I am not sure how to attach the photo
PizzaMaster
Click the 'Add an image icon' down below (next to link / dot-points)
Go to and upload ur image to: https://imgur.com/upload
Copy the link from the address bar, and add it in the space provided!
sorry that didn't seem to work for me
how about:
https://ibb.co/26R91Z3
PizzaMaster
Yeah I see what you mean....
I just tried plugging it into mol-view; which breaks whenever I try to render it / view it's name. Fair chance this molecule doesn't exist... but then again - its chemistry... So who knows.
Maybe Billzene?
What is the accepted equation for alkene hydration?
Is it done with H2 gas? I've read that it is done with steam(H2O) but my textbook says H2(g).
What does VCAA say?
Will
My Edrolo textbook (and what my teacher has taught) says that alkene hydration involves H2O, requiring phosphoric acid and heat as a catalyst (therefore, I'm assuming H2O would be steam due to the heat?). H2(g) is involved in alkene hydrogenation, and needs a metal catalyst (e.g. Ni). Just remember that when you hydrate, you're drinking water, so alkene hydration must involve water (and hydrogenation involves H2(g)). I'm not 100% sure if I'm correct, but that's what I've been taught.
Hydrogenation: Alkene + H2 (g) → Alkane: Ni(s)
Hydration: Alkene + H2O(g) → Alcohol: H3PO4 (H2SO4 also accepted)
_sophiestudies_ this is correct, VCAA said alkene hydration involves H2O(l) on my exam (2018) which was hilariously wrong
hi all! i just have a couple quick questions regarding calculations... sorry if these have already been asked!
when you are calculating the specific heat capacity of water, does vcaa expect us to convert mL to grams (as in multiply by 0.997)?
also when finding the percentage atom economy, do you have to take into account the coefficients in the given equation? like if it's 2H2O would you use 2x18 as the molar mass?
sorry if these don't make sense, I've just noticed a slight difference in given solutions across different papers
thanks in advance!!
bw304
Hello
Q1/ When you are doing calculations involving the equation q=mcΔT, only convert mL to grams if it specifically tells you that the experimental conditions are SLC because the density of water varies with temperature. If conditions are non SLC, then you can just assume mL of water = g of water.
Q2/ Atom Economy takes into account the stoichiometric ratios of the reaction.
SCENARIO
Observe the reaction below, where C is the desired product.
Reaction 1) 5A+5B → C +9D
Reaction 2) 5A+5B→9C+D
It would "make sense" that Reaction 2 has a higher atom economy because greater proportion of the reactants are being converted to the desired product (9C) as compared to Reaction 1, which has a lower atom economy as only 1 C is being produced.
Hope this makes sense
Also just randomly, Remember:
For the purpose of the VCE Chemistry Study Design, whole numbers will have the same significant figures as number of digits, for example 400 has three significant figures while 400.0 has four.
This keeps tricking me - lol
Hey all,
Quick qs.
Why is can this not be A wouldnt it still force a forward reaction in both reactions.
Dissolved carbon dioxide, CO2, can react with water, H2O, to form carbonic acid, H2CO3.
H2CO3 can also react with H2O to form bicarbonate ions, HCO3
–, and hydronium ions, H3O+.
CO2(aq) + H2O(l) ⇌ H2CO3(aq)
H2CO3(aq) + H2O(l) ⇌ HCO3
–(aq) + H3O+(aq)
A beaker that contains 2 L of deionised water is placed in a room and left overnight so that these two
reactions reach equilibrium. In the morning one change is made to the system.
Which one of the following changes is most likely to result in an increase in the concentration of H3O+ ions?
A. Dilute the solution.
B. Bubble in more CO2 gas.
C. Add a few drops of phenolphthalein indicator.
D. Add a few drops of 0.1 M sodium hydroxide, NaOH, solution.
Correct answer is B
While adding water is technically adding a reactant, and should effect the equilibrium, as it is water all it will do is dilute both sides equally, meaning that the concentrations of each are reduced proportionally to each other. Water is not used to determine the equilibrium constant(Kc), so I believe we ignore it when determining which way equilibriums will shift.
I'd appreciate it if other people could confirm
N1ck3lGall1um The effect of dilution will be greater than that of any H3O+ produced. However adding CO2 will prompt the system to use it up which favours the side with H+. That's why if you breathe in a paper bag for too long, your blood pH will drop (this is called respiratory acidosis)
Hey all, thanx for your help , but I got another one.
When the battery is fully charged, it has a lead, Pb, anode, a lead(IV) oxide, PbO2, cathode and
a sulfuric acid, H2SO4, electrolyte. When fully discharged, the two electrodes are both coated in
lead(II) sulfate, PbSO4.
Pb(s)(anode), H2SO4(aq)(electrolyte) and lead(IV) oxide PbO2(s) (cathode)
a. i. Write the oxidation reaction, including states, that occurs during discharge:
Pb(s) + H2SO4(aq) PbSO4(s) + 2H(aq) + 2e–
Pb(s) + SO42–(aq) PbSO4(s) + 2e–
Can someone please explain why H2SO4 is involved during oxidation .
Cant Pb just oxidise by itself to produce Pb2+
Hey guys, 1&2 chemistry here, do you have any tips for practical investigation posters? I’m not sure where I’m going with my discussion.
My poster is on a titration to find the concentration of CaCO3 (water hardness) and an evaporation to find TDS, I didn’t get any meaningful results as I didn’t understand how to perform a titration so my results section is suffering too.
N1ck3lGall1um You can't just show Pb as Pb2+ as that implies it's aqueous, whereas in fact you have a precipitate forming ie PbSO4.
hey guys! just a question...
when drawing a sequence of amino acids, can you draw each amino acid similar to how it is presented in the data book, or does vcaa expect you to show all bonds? like instead of NH2 doing H-N-H, etc?
tia!!