Bibliii
Make sure you have all the basics down pat, and understand what equations to ise when. Check if your library has any resources like the Oxford Study Buddy or ATARnotes topic tests. I found it really helped me. Understand your formula sheet, and write down any formulas that aren't on there, like the general equation of a sine or cosine function, things that are usueful. Use this when you are studying.

With math, the only way to actually study is by practicing. Practice heaps. Check out the QCAA exam examples. Recycle through different textbook questions - the cambridge one has really good ones. Talk to your school or local librarian and ask if they have year 12 methods resources - it always helps. You could check out the VCAA and HSC past exams, and pick out the ones that are relevant.

Hope this helped,
-jinx_58

      6 days later
      3 months later

      So I got confirmed 17/20 for my assignment and I'm so disappointed. I'm gonna make sure to ace the IA3 (cause otherwise I'm dead) so I'd love to help with questions when externals approach. I'm already studying for it. 🤓

      2 months later

      I'm still in year 10 so I'm not in a methods class yet, but will be next year. I just can't find the math question thread... So I'll ask it here. Out of linear, exponential, parabola, and quadratics for graphing, which one is best suited for recording the temperature of water every 5 mins (from hot to cold)?

        Leeshi Water cools proportional to its temperature differential so the diff eq will be dT/dt = -k(Twater - Tenvironment), where k is a constant of proportionality, Twater is temperature of the water after t min and Tenvironment is the temperature of the surroundings

        This will integrate to an exponential with the base e so you need an exponential model

          a year later

          hey! i'm not sure if anyone will reply in this thread, but i'm really confused about this question for my methods exam.
          The equation is y = 2sin (x) - 1, where the domain is from 0 to 3 pi. We were asked what the x-intercepts are.

          I understand you re-arrange to get sin(x) = 1/2, so the reference angle is pi/6.
          What do you do after this?
          They got 4 answers, until 3pi, but I don't understand how they got all of them, and why we getting all these answers?
          They are pi/6, 5pi/6, 13pi/6, 17pi/6

            sarah99

            Hey @sarah99,

            Sorry if it's too late but to answer that I'll go through the whole working out. So to summarise the question, it's solving the equation 𝑦 = 2 sin(𝑥)−1 for 𝑥 where 𝑦 = 0, over the domain 0≤𝑥≤3𝜋.
            2sin(𝑥)−1=0
            sin(𝑥)=1/2
            𝑥=𝜋/6 (which is correct with your reference angle you calculated too)

            So from there, you need to first draw out or see what x values equal to 𝜋/6 from 0 to 2𝜋 first. So obviously, that would be 𝑥=𝜋/6 in the first quadrant and then 𝑥=5𝜋/6 in the second quadrant (remember, these are quadrants where sin is positive). The other two quadrants in 0 to 2𝜋 don't have values for x since they will be negative.

            Now extending this to 3𝜋, you see that you are essentially extending to 180 degrees (or 𝜋). So here you get another two solutions that are in the first and second quadrant as well which will be essentially 2𝜋 plus the first two solutions we got so that will be 𝑥=2𝜋+𝜋/6=13𝜋/6 and 𝑥=2𝜋+5𝜋/6=17𝜋/6.

            So yeah all your solutions for 𝑥 will be 𝜋/6, 5𝜋/6, 13𝜋/6 and 17𝜋/6. Since there are two sets of quadrant 1 and 2 from 0 to 3𝜋.

            Anyways, hope that helps and let me know if you have any more questions!

            • PP

            ​

              2 months later

              Thank you so much for your reply!! I saw it just before my exam last year, but never got to reply, thank you.

              I saw this in my textbook, and was wondering what it means?
              If a function is one-to-one, then the image is the graph of a function. This is because if the function satisfies the horizontal line test, then its reflection will satisfy the vertical line test.
              I'm mainly confused about the bolded part.
              If anyone could please explain this, I'd really appreciate it!!
              Thank you so much!!

                sarah99 Im pretty sure it means like if it passes the horizontal line test which is basically where the function intersects the graph once then it will also only intersect the graph once vertically hence the one-to-one

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