So the methods sacs this year are worth 40%
But how much is u3 worth and how much is u4 worth?
Would really appreciate some help because im a bit confused, thanks!

They are combined into one graded assessment unlike some other subjects where GA1 is U3 and GA2 is U4.
Your end result or final ranking after unit 3 and 4 is what will form your GA1 for Methods.
GA2 is exam 1 and GA3 is exam 2.

Thankyou! But I was wondering more along the lines of for GA1 which is both units combined, is u4 sacs worth more than u3 sacs? I dont know if that makes sense sorry.

    Vel1 Last year, they added up all the marks from each sac across units 3/4 and totalled them up to reveal a final mark score out of 200 or something like that. These were then sent to vcaa to be converted into grades. Thats what happened in our school. We had 3 sacs in unit 3 and 2 in unit 4 so for us I suppose you could say unit 3 was worth more. Im not 100% sure on this and I think its ambiguous, different depending on how your school oragnises the sacs.

    • Vel1 replied to this.
        6 days later

        ah ok, yeah its probably different for all schools. Thanks!

        Revan
        A very over-asked question, I know...but I did extremely bad in my u3 sacs - 10 and 20% and was ranked last (because I did absolutely no work nor did I listen in class the entire year) We recently had our first u4 sac and I decided to change my game, studied really hard and got an 85% which is the second highest score in my cohort. Our cohort for methods is only 10 people and according to my teacher the sacs we do are very much vcaa exams level and often her sacs get brought up by a few percent. This year the top 3 of our cohort are pretty good with expected scores of 45, 40 and 38. The rest of our class is pretty mediocre. My rankings have definitely taken a hit, but say I continue on this path and do extremely well on the next sac and then the exam (90-95%) is it realistically possible for me to get a ss of around 38? Thankyou!

            Vel1 I think it is possible, but you are def going to have to change your game and get 90's at least or maybe mid 90's for all upcoming assessed work. Good Luck

              6 days later

              does anyone know how to work this out?
              A curve for which dy/dx=ekx, where k is a constant, is such that the tangent at (1,e2) passes through the origin. Find the gradient of this tangent and hence determine the value of k

                chemistry1111 so you'd first antidiff ekx which gets you ekx/k + c, which is your curve. You know one of the coordinates on the curve is (1,e2), so lets sub it into and make an equation. c + ek/k = e2. Now let's find the tangent of the curve at the given point. Go to CAS (menu -> 4-> 9) and u should type "tangentLine(f(x), x, 1)" which gets you the tangent line. Since it passes through origin you make it equal to zero and also sub in zero. You are now left with an equation containing only c and k. Take the equation from before and you have 2 equations. Solve using simultaneous equations and you should get k=2 and c=e2/2.

                Hope that helps

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